Question

Add to the code below so that when complied, it also shows the stalls which made a profit in increasing order of profit (lowest profit to highest profit) in output.txt

#include <iostream>
#include <fstream>// for file streaming
using namespace std;

int main()

{

struct Stall

{

string name;

double income;

double expenses;

double net;

};

double tprofit_loss = 0, most_profit;

Stall tmp;

int n = 0;

Stall Stalls[100];

bool loop = true;
ifstream f; //this is a input file object
f.open("stalls.txt"); //open file with the f object

ofstream of; //this is a output file object
of.open("output.txt"); //open file "output.txt" with the of object

while (loop)

{

f >> tmp.name; //read from the file

if (tmp.name == "xxxxxx")

{

loop = false;

continue;

}

f>> tmp.income; //read income from the file

f>> tmp.expenses; //read expenses from the file

tmp.net = tmp.income - tmp.expenses;

tprofit_loss += tmp.net;

if (n != 0)

if (Stalls[n-1].net >= tmp.net)

Stalls[n++] = tmp;

else

{

Stall tmp2 = Stalls[n-1];

Stalls[n-1] = tmp;

Stalls[n++] = tmp2;

}

else

{

Stalls[n++] = tmp;

}

}

of<< "Stall name\t" //write to the output file

<< "Net income" << endl;

for (int i = 0; i < n; i++)

of<< Stalls[i].name << "\t\t" << Stalls[i].net << endl;

of<< "Number of stalls in the bazar were: " << n << endl;

if (tprofit_loss < 0)

of << "Total loss of bazar is " << tprofit_loss << endl;

else

of << "Total profit of bazar is " << tprofit_loss << endl;

of << "Stalls with most profit are:" << endl;

most_profit = Stalls[0].net;

for (int i = 0; i < n && Stalls[i].net == most_profit; i++)

of << Stalls[i].name << ", ";

of << endl;

return 0;

}

Answer 1

If you have any doubts, please give me comment...

#include <iostream>

#include <fstream> // for file streaming

using namespace std;

struct Stall {

string name;

double income;

double expenses;

double net;

};

int main() {

double tprofit_loss = 0, most_profit;

Stall tmp;

int n = 0;

Stall Stalls[100];

bool loop = true;

ifstream f; // this is a input file object

f.open("stalls.txt"); // open file with the f object

ofstream of; // this is a output file object

of.open("output.txt"); // open file "output.txt" with the of object

while (loop) {

f >> tmp.name; // read from the file

if (tmp.name == "xxxxxx") {

loop = false;

continue;

}

f >> tmp.income; // read income from the file

f >> tmp.expenses; // read expenses from the file

tmp.net = tmp.income - tmp.expenses;

tprofit_loss += tmp.net;

Stalls[n] = tmp;

n++;

}

for (int i = 0; i < n; i++) {

for (int j = i + 1; j < n; j++) {

if (Stalls[i].net > Stalls[j].net) {

Stall tmp = Stalls[i];

Stalls[i] = Stalls[j];

Stalls[j] = tmp;

}

}

}

of << "Stall name\t" // write to the output file

<< "Net income" << endl;

for (int i = 0; i < n; i++)

of << Stalls[i].name << "\t\t" << Stalls[i].net << endl;

of << "Number of stalls in the bazar were: " << n << endl;

if (tprofit_loss < 0)

of << "Total loss of bazar is " << tprofit_loss << endl;

else

of << "Total profit of bazar is " << tprofit_loss << endl;

of << "Stalls with most profit are:" << endl;

most_profit = Stalls[n-1].net;

for (int i = n-1; i >=0 && Stalls[i].net == most_profit; i--)

of << Stalls[i].name << ", ";

of << endl;

return 0;

}