Question

The following electron configurations represent excited states. Identify the element and enter its ground-state condensed electron configuration:

1s^22s^22p^43s^1

[Ar]4s13d104p25p1

[Kr]5s24d25p1

Answer 1

The excited electronic configuration is 1s²2s²2p⁴3s¹

In this the electron jumps from 2p orbital to 3s orbital so the ground-state electronic configuration is 1s²2s²2p⁵

So the element with 2+2+5 = 9 electrons ( so At. number 9) is Fluorine(F)

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The excited electronic configuration is [Ar]4s¹3d¹⁰4p²5p¹

In this the electron jumps from 4s orbital to 5p orbital so the ground-state electronic configuration is [Ar]4s²3d¹⁰4p²

So the element with 18(for Ar) +2+10+2 = 32 electrons ( so At. number 32) is Germanium (Ge).

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The excited electronic configuration is [Kr]5s²4d²5p¹

In this the electron jumps from 4g orbital to 5p orbital so the ground-state electronic configuration is [Kr]5s²4d³

So the element with 36(for Kr) +2+3 = 41 electrons ( so At. number 41) is Niobium (Nb).