Question

In Java please:

3.39 Lab 6e: CharacterOps

Write a program that prompts the user to enter their first name. Say hello to the person. Then display whether their name begins with a vowel or consonant.
If it is neither, perhaps a special character or a number digit, then print neither a vowel nor a consonant.

Example 1:

Enter your first name:  Barbara
Hello, Barbara!
The first letter of your name, 'B', is a consonant.

Example 2:

Enter your first name:  Elizabeth
Hello, Elizabeth!
The first letter of your name, 'E', is a vowel.

Example 3:

Enter your first name:  !Sam
Hello, !Sam!
The first letter of your name, '!', is a is neither a vowel nor a consonant.

Java's Character class provides a method isAlphabetic() which may assist your coding effort.

Suppose we have char ch = 'm'; then Character.isAlphabetic(ch) would return true.
Likewise, Character.isAlphabetic('&') would return false.

Answer 1

import java.util.Scanner;

public class CharacterOps {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("Enter your first name: ");
        String name = in.nextLine();
        char ch = name.charAt(0);
        System.out.println("Hello, " + name + "!");
        if (Character.isAlphabetic(ch)) {
            ch = Character.toLowerCase(ch);
            if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
                System.out.println("The first letter of your name, '" + name.charAt(0) + "', is a vowel.");
            } else {
                System.out.println("The first letter of your name, '" + name.charAt(0) + "', is a consonant.");
            }
        } else {
            System.out.println("The first letter of your name, '" + ch + "', is a is neither a vowel nor a consonant.");
        }
    }
}