Question
In: Physics
A.) Find the work done by an ideal engine which extracts 8900.0 J of heat from...
A.) Find the work done by an ideal engine which extracts 8900.0 J of heat from its hot resevior while operating between 550.0 K and 370.0 K.
B.) The work from the engine goes into an ideal refridgerator which extracts 5300.0 J of heat from its cold resevior. FInd the coefficient of performance of the ideal refridgerator.
Solutions
Expert Solution
for an ideal heat engine
the efficiency formula is
T2 is lower temperature and T1 is heigher temperature
and 
w work done , Q is heat absorbed
combining these two we get work done by ideal heat engine is
= (1- 370/ 550)8900
= 2912.72 J
B) coefficient of performance = Q / W Q is heat extracted from the cold reservoir, W work done
= 5300 J / 2912.72 J
= 1.81
genius_generous answered 1 year agoRelated Solutions
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