Question

In: Chemistry

If a cylinder contains 12.0lb of liquid propane (C3H8), what volume does the propane occupy when...

If a cylinder contains 12.0lb of liquid propane (C3H8), what volume does the propane occupy when it has completely vaporized at STP?

Expert Solution

Ans. Mass of liquid propane = 12.0 lb = 12.0 x (453.592 g) = 5443.11 g

Moles of propane = Mass /Molar mass

= 5443.11 g / (44.09652 g/ mol)

= 123.4363 mol

# It’s assumed that vapor propane behave as ideal gas.

# Using Ideal gas equation: PV = nRT - equation 1

Where, P = pressure in atm

V = volume in L

n = number of moles

R = universal gas constant= 0.0821 atm L mol^-1K^-1

T = absolute temperature (in K) = (⁰C + 273.15) K

Putting the values in above equation -

1.00 atm x V = 123.4363 mol x (0.0821 atm L mol^-1K^-1) x 273.15 K

Or, V = 2768.1349 atm L^-1 / 1.00 atm

Hence, V = 2768.1349 L

Therefore, volume of propane vapor at STP = 2768.1349 L

queen_honey_blossom answered 2 years ago

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