In: Statistics and Probability
In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected.
Light | Heavy | |||
Nonbrowser | Browser | Browser | ||
6 | 7 | 4 | ||
7 | 8 | 6 | ||
8 | 7 | 4 | ||
5 | 6 | 6 | ||
5 | 9 | 3 | ||
6 | 6 | 5 | ||
7 | 8 | 4 | ||
6 | 7 | 6 |
a. Use @= 0.5 to test for a difference among mean comfort scores for the three types of browsers.
Compute the values identified below (to 2 decimals, if necessary).
Sum of Squares, Treatment | |
Sum of Squares, Error | |
Mean Squares, Treatment | |
Mean Squares, Error |
Calculate the value of the test statistic (to 2 decimals, if necessary).
The p-value is - Select your answer (-less than .01) (between .01 and .025) (between .025 and .05) (between .05 and .10) (greater than .10) Item 6 What is your conclusion? - Select your answer -(Conclude that the mean comfort scores are not all the same for the browser groups) (Do not reject the assumption that the mean comfort scores are equal for the browser groups) Item 7b. Use Fisher's LSD procedure to compare the comfort levels of non browsers and light browsers. Use . Compute the LSD critical value (to 2 decimals). What is your conclusion? - Select your answer -(Conclude that non browsers and light browsers have different mean comfort scores) (Cannot conclude that non browsers and light browsers have different mean comfort scores) Item 9 |