Question
In: Statistics and Probability
Marla is studying the sodium content of cold cuts. A random sample of 8 52-gm samples...
Marla is studying the sodium content of cold cuts. A random sample of 8 52-gm samples of smoked beef produced sample mean 14.04 gm of sodium with sample standard deviation 0.50 gm. An independent random sample of 6 52-gm samples of smoked turkey produced sample mean 13.52 gm sodium with sample standard deviation 0.75 gm. Test the claim that there is a difference in the mean sodium content of the above brands of smoked ham and smoked turkey. Use a 5% significance level. Assume that population variances are not equal.
Solutions
orchestra answered 2 years agoRelated Solutions
Measurements of the sodium content in samples of two brands of chocolate bar yield the following...
Measurements of the sodium content in samples of two brands of
chocolate bar yield the following results (in grams):
Brand A: 34.36 31.26 37.36
28.52 33.14
32.74 34.34
34.33 33.95
Brand B: 41.08 38.22 39.59
38.82 36.24
37.73 35.03
39.22 34.13
34.33 34.98
29.64 40.60
Let μXμX represent the population mean for Brand B and let μYμY
represent the population mean for Brand A. Find a 98% confidence
interval for the difference μX−μYμX−μY. Round down the degrees of
freedom to...
Measurements of the sodium content in samples of two brands of chocolate bar yield the following...
Measurements of the sodium content in samples of two brands of
chocolate bar yield the following results (in grams):
Brand A: 34.36 31.26 37.36
28.52 33.14
32.74 34.34
34.33 27.95
Brand B: 41.08 38.22 39.59
38.82 36.24
37.73 35.03
39.22 34.13
34.33 34.98
29.64 40.60
Let μXμX represent the population mean for Brand B and let μYμY
represent the population mean for Brand A. Find a 98% confidence
interval for the difference μX−μYμX−μY. Round down the degrees of
freedom to...
2. A new method is developed to determine the content of sodium in a biscuit sample....
2. A new method is developed to determine the content of sodium
in a biscuit sample. Student A gets the following results: 24.2,
23.9, 25.0, 23.7 and 25.2 mg, while student B obtains 22.6, 21.9,
23.2 and 23.1 mg.
(a) Report 95% confidence interval of their results
individually. Why the standard deviations are non-zero?
(b) At the 95% confidence level, does one of them get more
reproducible measurements?
(c) At the 95% confidence level, do they obtain different
results? What...
4. A researcher testing sodium content of snack foods examines samples of two brands of potato...
4. A researcher testing sodium content of snack foods
examines samples of two brands of potato chips that both claim to
be low in sodium. A random sample of 25 lunch-size bags of chips
for Super Chips indicates an average of 80 milligrams of sodium per
bag, with a standard deviation of 5 milligrams. A second sample of
22 lunch-size bags of Real Potato Snacks shows an average of 77
milligrams of sodium per bag, with a standard deviation of...
8. [5 marks] You are studying two normally distributed populations with equal variances. A random sample...
8. [5 marks] You are studying two normally distributed
populations with equal variances. A random sample of size 10 is
taken from each population. The sample from the first population
gives the following measurements: 16, 14, 19, 18, 19, 20, 15, 18,
17, 18. The sample from the second population gives the following
measurements: 13, 19, 14, 17, 21, 14, 15, 10, 13, 15. Compute a 95%
confidence interval for the difference between two population
means.
A simple random sample with n=52 provided a sample mean of 24.0 and a sample standard...
A simple random sample with n=52 provided a sample mean of 24.0
and a sample standard deviation of 4.5.
a. Develop a 90% confidence interval for the
population mean (to 1 decimal).
,
b. Develop a 95% confidence interval for the
population mean (to 1 decimal).
,
c. Develop a 99% confidence interval for the
population mean (to 1 decimal).
,
d. What happens to the margin of error and the
confidence interval as the confidence level is increased?
In studying the dairy food expenditure of families in a city, random samples of fifty families...
In studying the dairy food expenditure of families in a city,
random samples of fifty families and forty families are selected
from urban area and rural area, respectively. Selected families
from urban area have a mean of $150 and a standard deviation of
$30. Selected families from rural area have a mean of $135 and a
standard deviation of $25. Construct a 95% confidence interval for
the difference of mean daily food expenditure between all families
of urban area and...
A sample of 52 Elementary Statistics students includes 13 women. Assuming the sample is random: (a)...
A sample of 52 Elementary Statistics students includes 13 women.
Assuming the sample is random:
(a) Estimate the percentage of women taking Elementary
Statistics by computing an appropriate confidence interval with 98%
confidence.
(b) At 10% significance, test whether less than 40% of the
enrollment in all Elementary Statistics classes consists of
women.
The following data represent soil water content (percentage of water by volume) for independent random samples...
The following data represent soil water content (percentage of
water by volume) for independent random samples of soil taken from
two experimental fields growing bell peppers. Soil water content
from field I: x1; n1 = 72 15.1 11.3 10.1 10.8 16.6 8.3 9.1 12.3 9.1
14.3 10.7 16.1 10.2 15.2 8.9 9.5 9.6 11.3 14.0 11.3 15.6 11.2 13.8
9.0 8.4 8.2 12.0 13.9 11.6 16.0 9.6 11.4 8.4 8.0 14.1 10.9 13.2
13.8 14.6 10.2 11.5 13.1 14.7 12.5...
The following data represent soil water content (percentage of water by volume) for independent random samples...
The following data represent soil water content (percentage of
water by volume) for independent random samples of soil taken from
two experimental fields growing bell peppers.
Soil water content from field I: x1; n1 = 72
15.2 11.3 10.1 10.8 16.6 8.3 9.1 12.3 9.1 14.3 10.7 16.1 10.2
15.2 8.9 9.5 9.6 11.3 14.0 11.3 15.6 11.2 13.8 9.0 8.4 8.2 12.0
13.9 11.6 16.0 9.6 11.4 8.4 8.0 14.1 10.9 13.2 13.8 14.6 10.2 11.5
13.1 14.7 12.5...
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