In: Chemistry
Ascorbic acid (vitamin C, C6H8O6) is a water-soluble vitamin. A solution containing 81.0 g of ascorbic acid dissolved in 220 g of water has a density of 1.22 g/mL at 55 ∘C.
Calculate the mass percentage.
Calculate the mole fraction.
Calculate the molality.
Calculate the molarity of ascorbic acid in this solution.
mass of solution = 81+220 = 301g
The mass percentage = 81*100/301 = 26.9%
no of moles of ascorbic acid = W/G.M.Wt = 81/176 = 0.46moles
no of moles of water = W/G.M.Wt = 220/18 = 12.22 moles
molae fraction of ascorbic acid = no of moles of ascorbic acid/no of moles of ascorbic acid + no of moles of water
= 0.46/0.46+12.22
= 0.46/12.68 = 0.0363
molality = W*1000/gram molar mass * weight of solvent
= 81*1000/176*220 = 2.09m
volume of solution = 220/1.22 = 180.32ml
molarity = 81*1000/176*180.32 = 2.55M