Ascorbic acid (vitamin C, C6H8O6) is a water-soluble vitamin. A solution containing 81.0 g of ascorbic...

Ascorbic acid (vitamin C, C6H8O6) is a water-soluble vitamin. A solution containing 81.0 g of ascorbic acid dissolved in 220 g of water has a density of 1.22 g/mL at 55 ∘C.

Calculate the mass percentage.

Calculate the mole fraction.

Calculate the molality.

Calculate the molarity of ascorbic acid in this solution.

Solutions

Expert Solution

mass of solution = 81+220 = 301g

The mass percentage = 81*100/301 = 26.9%

no of moles of ascorbic acid = W/G.M.Wt = 81/176 = 0.46moles

no of moles of water = W/G.M.Wt = 220/18 = 12.22 moles

molae fraction of ascorbic acid = no of moles of ascorbic acid/no of moles of ascorbic acid + no of moles of water

= 0.46/0.46+12.22

= 0.46/12.68 = 0.0363

molality = W*1000/gram molar mass * weight of solvent

= 81*1000/176*220 = 2.09m

volume of solution = 220/1.22 = 180.32ml

molarity = 81*1000/176*180.32 = 2.55M

queen_honey_blossom answered 7 months ago

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