Question

How do we compare the mass of the ascorbic acid in vitamin c pill with the advertised value statistically in excel? What test do we use. Explain it in detail. You can use random numbers to make the explanation more clear.

Answer 1

vitamin pills with advertise contents includes 750 mg ascorbic acid.

so student take whole pill, and crushed and disolves in all water. Then diluted the pill solution to find the volume 250.0 ml.

They analyse 20 ml aliquots solution of abscorbic acd by titration using standardise iodine solution.

Final volume contain pill = 250.0

Analysed volume of pill solution = 20.0 ml

standard iodine solution concentration = 0.0198 mol L^-1

Average titration = 17.71 ml

Calculation :

Amount of moles of abscorbic acid per 20 ml = 0.0198mol/L * 0.01771 L

=0.00350658 mol

To find amount of entire 250 ml solution = 12.5 * 0.00350658 mol

=0.004383225 mol

multiply this by molar mass of ascorbic acid(17.14 g/mol) ti get gram of ascorbic acid

=176.14 * 0.004383225

=0.7718859225 g

For milligram we multiply this by 1000 mg/1 g

   =0.7718859225 * 1000 mg/1 g

   =771.8859225 mg

   =722 mg

so in this way we compare the mass of ascorbic acid in vitamin c pill that is 722 mg and advertise vlaue that is 750 mg

The method we use is titration against standardise iodine solution.