In: Physics
A retaining wall against a mud slide is to be constructed by placing 1.2 m-high rectangular concrete blocks (ρconcrete = 2700 kg/m3 ) side by side, as shown in Figure 1. The friction coefficient between the ground and the concrete blocks is f = 0.3, and the density of the mud is about 1800 kg/m3 . There is concern that the concrete blocks may slide or tip over the lower left edge as the mud level rises.
a) Determine the minimum width w of the concrete blocks at which the blocks will overcome friction and start sliding. Plot the results over the mud height ranging from zero to the top of the retaining wall in 0.2 m-increments.
b) Determine the minimum width w of the concrete blocks at which the blocks will tip over. Plot the results over the mud height ranging from zero to the top of the retaining wall in 0.2 m-increments in the same graph as a).
c) Briefly comment on the results.
Assumptions : Atmospheric pressure acts
on both sides of the wall, and thus it can be ignored in
calculations for convenience.
Properties : The density is given to be
1800 kg/m3 for the mud, and 2700 kg/m3 for concrete blocks.
Analysis : (a) The weight of the concrete
wall per unit length (L = 1 m) and the friction force between the
wall and the ground are
Wblock = rho*g*v= 2700*9.81*0.2*0.8*1 = 4238 N
The hydrostatic force exerted by the mud to the wall is
FH = Fx = Pavg*A = rho*g*(h/2)*A = 1800*9.81*(h/2)*h = 8829*h^2 N
Setting the hydrostatic and friction forces equal to each other
gives
FH = Ffriction
8829*h^2 = 1271
h = 0.38 m
(b) The line of action of the hydrostatic force passes through
the pressure center, which is 2h/3 from the free surface. The line
of action of the weight of the wall passes through the midplane of
the wall. Taking the moment about point A and setting it equal to
zero gives
Sigma MA = 0
Wblock(t/2) = FH(h/3)
Wblock(t/2) = 8829h^3/3
Solving for h and substituting, the mud height for tip over is
determined to be
h = (3Wblock*t/(2*8829))^(1/3) = (3*4238*0.2/(2*8829))^(1/3 = 0.52 m
Discussion The concrete wall will slide before tipping. Therefore, sliding is more critical than tipping in this case.