In: Statistics and Probability
A botanist wishes to estimate the typical number of seeds for a
certain fruit. She samples 36 specimens and counts the number of
seeds in each. Use her sample results (mean = 76.3, standard
deviation = 10.8) to find the 99% confidence interval for the
number of seeds for the species. Enter your answer as an
open-interval (i.e., parentheses)
accurate to 1 decimal place.  
99% C.I. =
We have given that,      
   
          
Sample mean =76.3  
Sample standard deviation =10.8
Sample size =36  
Level of significance=   0.01  
Degree of freedom =35  
          
t critical value is (by using t table)=   2.724
          
Confidence interval formula is   
=(71.4,81.2)      
          
          
          
Lower confidence limit=   71.4  
          
Upper confidence limit=   81.2