In: Statistics and Probability
A botanist wishes to estimate the typical number of seeds for a
certain fruit. She samples 36 specimens and counts the number of
seeds in each. Use her sample results (mean = 76.3, standard
deviation = 10.8) to find the 99% confidence interval for the
number of seeds for the species. Enter your answer as an
open-interval (i.e., parentheses)
accurate to 1 decimal place.
99% C.I. =
We have given that,
Sample mean =76.3
Sample standard deviation =10.8
Sample size =36
Level of significance= 0.01
Degree of freedom =35
t critical value is (by using t table)= 2.724
Confidence interval formula is
=(71.4,81.2)
Lower confidence limit= 71.4
Upper confidence limit= 81.2