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A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples...

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 49 specimens and counts the number of seeds in each. Use her sample results (mean = 68.6, standard deviation = 14.2) to find the 80% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.  

80% C.I. =

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Solution :

It is given that a botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 49 specimens and counts the number of seeds in each. We have to use her sample results (mean = 68.6, standard deviation = 14.2) to find the 80% confidence interval for the number of seeds for the species.

Let be the mean number of seeds for the species.

We know that the 100 (1)% Confidence Interval for Population Mean () is given as ,

Thus , the data that we have from the given information are ,

Thus , the 80% Confidence Interval for Population Mean () is given as ,

  

  

  

  

  

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