In: Statistics and Probability
A medical researcher wants to construct a 99% confidence interval for the proportion of knee replacement surgeries that result in complications. An article in the Journal of Bone and Joint Surgery suggested that approximately 8% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.047 ? Write only an integer as your answer.
Sample size estimation for proportion
Preliminary estimate for proportion (Known) =
0.08
Margin of error =E=0.047
Level of significance =1-0.99= 0.01
Z critical value is (by using Z table)=2.58
Sample size
=221.06
Therefore, sample size approximately will be 222