In: Statistics and Probability
A medical researcher wants to construct a 99% confidence interval for the proportion of knee replacement surgeries that result in complications. An article in the Journal of Bone and Joint Surgery suggested that approximately 8% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.047 ? Write only an integer as your answer.
Sample size estimation for proportion  
           
           
   
          
           
       
Preliminary estimate for proportion (Known) =   
0.08          
Margin of error =E=0.047      
   
Level of significance =1-0.99=   0.01  
       
Z critical value is (by using Z table)=2.58  
       
          
           
       
Sample size
=221.06
Therefore, sample size approximately will be 222