Question
In: Statistics and Probability
3) Kim wants to determine a 99 percent confidence interval for the true proportion p of...
3) Kim wants to determine a 99 percent confidence interval for
the true proportion p of high school students in the area who
attend their home basketball games. Out of ?n randomly selected
students she finds that that exactly half attend their home
basketball games. About how large would ?n have to be to get a
margin of error less than 0.01 for p?
[Use the values for z* from a z-table or t-table, and round to the
smallest integer that works.]
n≈
2) A random sample of 1100 car owners in a particular city found 539 car owners who received a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.
Answer:
to %
3) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living below the poverty line.
(Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places).
95% confidence interval = (. , )
Solutions
orchestra answered 2 years agoRelated Solutions
1. Beth wants to determine a 95 percent confidence interval for the true proportion of high...
1. Beth wants to determine a 95 percent confidence interval for
the true proportion of high school students in the area who attend
their home basketball games. How large of a sample must she have to
get a margin of error less than 0.02?
HINT: To find n, since no previous study has been done, use the
value p = 0.5 for the proportion and one of the values (1.282,
1.645, 1.96, 2.576) for the critical value depending on the...
Determine the margin of error for a 99% confidence interval to estimate the population proportion with...
Determine the margin of error for a 99% confidence interval to
estimate the population proportion with a sample proportion equal
to 0.80 for the following sample sizes.
a. n=100 b. n=200 c. n=260
A medical researcher wants to construct a 99% confidence interval for the proportion of knee replacement...
A medical researcher wants to construct a 99% confidence
interval for the proportion of knee replacement surgeries that
result in complications. An article in the Journal of Bone and
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result in complications. Using this estimate, what sample size is
needed so that the confidence interval will have a margin of error
of 0.047 ? Write only an integer as your answer.
Compute the 99% confidence interval estimate for the population proportion, p, based on a sample size...
Compute the 99% confidence interval estimate for the population
proportion, p, based on a sample size of 100 when the sample
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Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 99% confidence interval to estimate the population
proportion with a sample proportion equal to 0.90 and a sample size
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------A 99% confidence interval estimates that the population
proportion is between a lower limit of ___ and an upper limit of
___.
????????
Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 99% confidence interval to estimate the population
proportion with a sample proportion equal to 0.50 and a sample size
equal to 200. LOADING... Click the icon to view a portion of the
Cumulative Probabilities for the Standard Normal Distribution
table. A 99% confidence interval estimates that the population
proportion is between a lower limit of nothing and an upper limit
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A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 99% confidence
interval for the proportion of all Americans who are in favor of a
new Green initiative. Of the 590 randomly selected Americans
surveyed, 410 were in favor of the initiative. Round answers to 4
decimal places where possible.
a. With 99% confidence the proportion of all Americans who favor
the new Green initiative is between and .
b. If many groups of 590 randomly selected Americans were
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A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 99% confidence
interval for the proportion of all Americans who are in favor of a
new Green initiative. Of the 534 randomly selected Americans
surveyed, 400 were in favor of the initiative.
a. With 99% confidence the proportion of all Americans who favor
the new Green initiative is between -- and --.
b. If many groups of 534 randomly selected Americans were
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You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that...
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lived to become butterflies.
a. With 99% confidence the proportion of all caterpillars that
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contain...
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