Question
In: Statistics and Probability
3) Kim wants to determine a 99 percent confidence interval for the true proportion p of...
3) Kim wants to determine a 99 percent confidence interval for
the true proportion p of high school students in the area who
attend their home basketball games. Out of ?n randomly selected
students she finds that that exactly half attend their home
basketball games. About how large would ?n have to be to get a
margin of error less than 0.01 for p?
[Use the values for z* from a z-table or t-table, and round to the
smallest integer that works.]
n≈
2) A random sample of 1100 car owners in a particular city found 539 car owners who received a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year. Express your results to the nearest hundredth of a percent.
Answer:
to %
3) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living below the poverty line.
(Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places).
95% confidence interval = (. , )
Solutions
orchestra answered 1 year agoRelated Solutions
1. Beth wants to determine a 95 percent confidence interval for the true proportion of high...
1. Beth wants to determine a 95 percent confidence interval for
the true proportion of high school students in the area who attend
their home basketball games. How large of a sample must she have to
get a margin of error less than 0.02?
HINT: To find n, since no previous study has been done, use the
value p = 0.5 for the proportion and one of the values (1.282,
1.645, 1.96, 2.576) for the critical value depending on the...
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Compute the 99% confidence interval estimate for the population
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Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 99% confidence interval to estimate the population
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------A 99% confidence interval estimates that the population
proportion is between a lower limit of ___ and an upper limit of
___.
????????
Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to...
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Cumulative Probabilities for the Standard Normal Distribution
table. A 99% confidence interval estimates that the population
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A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 99% confidence
interval for the proportion of all Americans who are in favor of a
new Green initiative. Of the 590 randomly selected Americans
surveyed, 410 were in favor of the initiative. Round answers to 4
decimal places where possible.
a. With 99% confidence the proportion of all Americans who favor
the new Green initiative is between and .
b. If many groups of 590 randomly selected Americans were
surveyed, then a different...
A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 99% confidence
interval for the proportion of all Americans who are in favor of a
new Green initiative. Of the 534 randomly selected Americans
surveyed, 400 were in favor of the initiative.
a. With 99% confidence the proportion of all Americans who favor
the new Green initiative is between -- and --.
b. If many groups of 534 randomly selected Americans were
surveyed, then a different confidence interval would be produced
from each...
A psychologist is interested in constructing a 99% confidence interval for the proportion of people who...
A psychologist is interested in constructing a 99% confidence
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You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that...
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lived to become butterflies.
a. With 99% confidence the proportion of all caterpillars that
lived to become a butterfly is between and .
b. If many groups of 436 randomly selected caterpillars were
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A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans...
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interval for the proportion of all Americans who are in favor of a
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