In: Math
Let Q1, Q2, Q3, Q4 be constants so that R (2x + 3) sin 4x dx = (Q1x + Q2) sin 4x + (Q3x+Q4) cos 4x+C, where C is a constant of integration. Let Q = ln(3 +|Q1|+ 2|Q2|+ 3|Q3| + 4|Q4|). Then T = 5 sin2 (100Q)
satisfies:— (A) 0 ≤ T < 1. — (B) 1 ≤ T < 2. — (C) 2 ≤ T < 3. — (D) 3 ≤ T < 4. — (E) 4 ≤ T ≤ 5.