Question

Three small airplanes flight a 1000-mile route. Write a program that inputs the airplane make,
model, and the number of gallons of fuel used by each airplane. After calling a calcMPG()
function once for each airplane have main determine and display which airplane is the most
fuel-efficient, and how many miles per gallon it got. The calcMPG() function should be passed
the distance flew and the gallons of gas consumed as arguments and should return the miles
per gallon obtained. Code must be written in C++

Answer 1

Answer: Hey!! Kindly finds your solution below. Let me know if any issue.Thanks.

Copy to Code: This code has function to calculate MPG of an airplane that return MPG of airplane. In main, user input information about all three airplanes and calculate their MPG store into an array, Then compare all MPG's and find max and print info about that airplane that gives best MPG.

#include<iostream>
using namespace std;
double calcMPG(double dis,double gallons)//function calcMPG() takes arguments
{
   double miles;
   miles = dis/gallons;
   return miles;
}
int main()
{
   string make[3],model[3];//arrays and variables
   double miles[3],d = 1000,g,temp;
  
   for(int i=0;i<3;i++)//for loop to take inputs for three airplanes
   {   cout<<"Enter airplane make: ";
       cin>>make[i];//takes input for make
       cout<<"enter airplane model: ";
       cin>>model[i];//takes input for model
       cout<<"Enter gallons of gas used: ";
       cin>>g;//takes input for gallons gas
       miles[i] = calcMPG(d,g);//call function to get MPG
   }
   temp = miles[0];
   int c =1;
   for(int i=1;i<3;i++)//find Fuel-Efficient plane (which MPG is max)
   {
       if(temp<miles[i])
       {
           temp=miles[i];
           c = i;
       }
   }
   cout<<"Fuel-Efficient airplane: ";//print info about Fuel-Efficient plane
   cout<<"\nAirplane Make: "<<make[c];
   cout<<"\nModel: "<<model[c];
   cout<<"\nMPG: "<<temp;
   return 0;
}
      
Screenshot of code and output: