In: Chemistry
Calculate the pH of a solution made by adding 44.0 g of sodium
formate, NaHCOO, to 200. mL of 0.23 M formic acid, HCOOH. Hint what
kind of solution is made?
The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal
places.
moles of NaHCOO = mass / molar mass
= 44.0 / 68.0
= 0.647
moles of HCOOH = volume x molarity
= 0.200 x 0.23
= 0.046
pKa = -log Ka
pKa = -log (1.8 x 10^-4) = 3.74
it is buffer solution ;
pH = pKa + log [NaHCOO / HCOOH]
pH = 3.74 + log (0.647 / 0.046)
pH = 4.89