Question

In: Chemistry

Calculate the pH of a solution made by adding 44.0 g of sodium formate, NaHCOO, to...

Calculate the pH of a solution made by adding 44.0 g of sodium formate, NaHCOO, to 200. mL of 0.23 M formic acid, HCOOH. Hint what kind of solution is made?

The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places.

Solutions

Expert Solution

moles of NaHCOO = mass / molar mass

                               = 44.0 / 68.0

                              = 0.647

moles of HCOOH = volume x molarity

                             = 0.200 x 0.23

                            = 0.046

pKa = -log Ka

pKa = -log (1.8 x 10^-4) = 3.74

it is buffer solution ;

pH = pKa + log [NaHCOO / HCOOH]

pH = 3.74 + log (0.647 / 0.046)

pH = 4.89


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