Codeine (C18H12NO3) is a weak organic base when dissolved in water. It ionizes as follows: C18H12NO3...

Codeine (C₁₈H₁₂NO₃) is a weak organic base when dissolved in water. It ionizes as follows:

C₁₈H₁₂NO₃ (aq) + H₂O ⇌ C₁₈H₁₂NO₃H⁺ (aq) + OH^- (aq)

The pH of a 5.0 * 10 ^-3 M solution of codeine equals 9.95. What is the equilibrium concentration of Codeine [C₁₈H₁₂NO]_eq in this solution?

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Expert Solution

C₁₈H₁₂NO₃ (aq) + H₂O <---------------> C₁₈H₁₂NO₃H⁺ (aq) + OH^- (aq)

0.005 M 0 0

0.005 - x x x

pH = 9.95

pOH = 4.05

[OH-] = 8.91 x 10^-5 M

x = [OH-] = 8.91 x 10^-5

equilibrium concentration of codeine = 0.005 - x

= 0.005 - 8.91 x 10^-5

equilibrium concentration of codeine = 4.9 x 10^-3 M

queen_honey_blossom answered 1 year ago

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