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Codeine (C18H12NO3) is a weak organic base when dissolved in water. It ionizes as follows: C18H12NO3...

Codeine (C18H12NO3) is a weak organic base when dissolved in water. It ionizes as follows:

C18H12NO3 (aq) + H2O ⇌ C18H12NO3H+ (aq) + OH- (aq)

The pH of a 5.0 * 10 -3 M solution of codeine equals 9.95. What is the equilibrium concentration of Codeine [C18H12NO]eq in this solution?

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Expert Solution

C18H12NO3 (aq) + H2O <---------------> C18H12NO3H+ (aq) + OH- (aq)

    0.005 M                                                   0                         0

   0.005 - x                                                   x                          x

pH = 9.95

pOH = 4.05

[OH-] = 8.91 x 10^-5 M

x = [OH-] = 8.91 x 10^-5

equilibrium concentration of codeine = 0.005 - x

                                                         = 0.005 - 8.91 x 10^-5

equilibrium concentration of codeine = 4.9 x 10^-3 M

queen_honey_blossom answered 2 years ago
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