Question
In: Chemistry
What is the pH of 0.51 M diethylammonium bromide, (C2H5)2NH2Br. The Kb of diethylamine, (C2H5)2NH, is...
What is the pH of 0.51 M diethylammonium bromide,
(C2H5)2NH2Br.
The Kb of diethylamine,
(C2H5)2NH, is 6.9 x
10-4.
Solutions
Expert Solution
(C2H5)2NH2Br it is a salt of strong acid and weak base. so cation participate in the reaction
(C2H5)2NH2+ + H2O ---------------------> (C2H5)2NH2 + H3O+
0.51 0 0
0.51 - x x x
Ka = Kw / Kb = 1.0 x 10^-14 / 6.9 x 10-4. = 1.45 x 10^-11
Ka = [ (C2H5)2NH2 ][H3O+] / [(C2H5)2NH2+ ]
1.45 x 10^-11 = x^2 / 0.51 - x
x = 2.71 x 10^-6
[H3O+] = x = 2.71 x 10^-6 M
pH = -log[H3O+]
= -log (2.71 x 10^-6)
= 5.57
pH = 5.57
queen_honey_blossom answered 1 year agoRelated Solutions
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