In: Chemistry
queous KNO3 solution is made using 84.7 g of KNO3 diluted to a total solution volume of 2.06 L . (Assume a density of 1.05 g/mL for the solution For this solution, calculate percent by mass For this solution, calculate mole fraction.
volume of solution = 2.06L = 2060ml
mass of KNO3 = 84.7g
mass of solution = volume of solution * density of solution
= 2060ml*1.05 g/ml = 2163g
percent by mass in the solution = mass of solute*100/ mass of solution
= 84.7*100/2163 = 3.92%
mass of H2O = mass of solution - mass of KNO3
= 2163-84.7 = 2078.3g
no of moles of H2O (n H2O) = W/G.M.Wt
= 2078.3/18 = 115.46moles
no of moles of KNO3 (n KNO3) = W/G.M.Wt
= 84.7/101 = 0.8386moles
mole fraction of KNO3 = n KNO3/n KNO3 + n H2O
= 0.8386/0.8386+115.46
= 0.8386/116.2986 = 0.0072