In: Chemistry
1.
b.Deduce the type of bonding experienced by calcium oxide, showing your calculations.
2.
e. Identify all spectator ions.
Q1: Electronegativity: It is a measure of how strongly atoms
attract bonding electrons towards themselves. Electronegativity is
expressed by the Greek letter:
. The higher the electronegativity, the greater an atom’s
attraction for electrons.
In the periodic table, electronegativity of elements increases from
the bottom of a group to the top and left to right across a
period.
Q2: Calcium oxide molecule is formed by the calcium cation
(Ca2+) and the oxygen anion (O2-).
Now, Ca is highly electropositive alkaline earth metal while oxygen
is highly electronegative non-metal. Hence,
Ca
Ca2+ + 2e-
O + 2e-
O2-
Therefore, Ca2+ + O2-
CaO
Ca and oxygen form a ionic bond. The calcium oxide ionic lattice is
cubic and similar to NaCl lattice, with an ion surrounded by 6
negatively charged oxygen ions.
Q3: When a solution of Calcium nitrate is mixed with a solution of
sodium sulfate, a precipitate forms. Therefore, the equation is
:
Ca(NO3)2 +
Na2SO4
CaSO4 + NaNO3
Therefore, the balanced equation is:
Ca(NO3)2 + Na2SO4 =
CaSO4 + 2NaNO3
Q4: The solid precipitate is CaSO4 as it has formed
in the solid form. Therefore, the equation with state symbols would
be,
Ca(NO3)2(aq) +
Na2SO4(aq) = CaSO4(s) +
2NaNO3(aq)
Where, ‘aq’ stands for aqueous form and‘s’ stands for ‘solid’
form.