Question

If an AaBbCcdd male mates with an AaBbCCDD female

a. What is the minimum number of ridge-producing alleles possible in one of their children?

b. What would be the TRC for this child if it is a male?

c. What would be the TRC for this child if it is a female?

d. If this child is a male, will he have a higher or lower TRC than the parent with the lower ridge count?

e. What is the maximum number of ridge-producing alleles possible in a child of this couple?

f. If this child is a female, will she have a higher or lower TRC than the parent with the higher ridge count?

This is exactly all the information given to me for this question.

Please help me with all the questions, im confused. I've seen this question asked multiple times and all the answers are different.

Answer 1

Solution:-

Parental cross: AaBbCcdd (male) x AaBbCCDD (female)

Punnet square

	ABCd	ABcd	AbCd	Abcd	aBCd	aBcd	abCd	abcd
ABCD	AABBCCDd	AABBCcDd	AABbCCDd	AABbCcDd	AaBBCCDd	AaBBCcDd	AaBbCCDd	AaBbCcDd
AbCD	AABbCCDd	AABbCcDd	AAbbCCDd	AAbbCcDd	AaBbCCDd	AaBbCcDd	AabbCCDd	AabbCcDd
aBCD	AaBBCCDd	AaBBCcDd	AaBbCCDD	AaBbCcDd	aaBBCCDd	aaBBCcDd	aaBbCCDd	aaBbCcDd
abCD	AaBbCCDd	AaBbCcDd	AabbCCDd	AabbCcDd	aabBCCDd	aaBbCcDd	aabbCCDd	aabbCcDd

a) What is the minimum number of ridge-producing alleles possible in of the children?

Each dominant allele (active allele) contributed to the phenotype in smaller and equal proportions.

The genotype "aabbCcDd" has only two dominant alleles "C" and "D" which contribute to the phenotype.

So, the answer is TWO.

b) What would be the TRC for the child if it is a male.

(Assuming here that each active allele adds 30 ridges to the TRC and genotype "aabbccdd" produce a baseline TRC of 40 for males and 20 for females)

So, male having genotype "aabbCcdD" produce 40+2x30 = 100 ridges.

c)b) What would be the TRC for the child if it is a female.

(Assuming here that each active allele adds 30 ridges to the TRC and genotype "aabbccdd" produce a baseline TRC of 40 for males and 20 for females)

So, the female having genotype "aabbCcDd" produce 20+(2x30) = 80 ridges

d) If this child is a male, will he have a higher or lower TRC than the parent with the lower ridge count?

Ridge count of both parents are,

AaBbCcdd (MALE) = 40+(3X30) = 130

AaBbCCDD(FEMALE)= 20+(6X30)= 200

The male child with genotype "aabbCcDd" has a ridge count of 100, whereas the parent with lower ridge count has 130.

So, the male child with minimum ridge-producing allele have lesser ridges than a parent with the lower ridge count.

e) What is the maximum number of ridge-producing alleles possible in a child of this couple?

The genotype "AABBCCDd" has 7 dominant alleles which contribute to the phenotype.

So, the answer is "SEVEN"

f) If this child is a female, will she have a higher or lower TRC than the parent with the higher ridge count?

AABBCCDd (female)= 20+(7x30) = 230 ridges

Parents

AaBbCcdd (MALE) = 40+(3X30) = 130

AaBbCCDD(FEMALE)= 20+(6X30)= 200

The parent with highest ridge count has 200 ridges. The female child has 230 ridges.

So, the female child with maximum ridge-producing allele have higher ridges than parent with the highest ridge count.