Question
In: Statistics and Probability
Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic...
Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic drinks that each consumes on a typical weekend. The data is below:
Females (Population 1): 2, 2, 2, 1, 3, 1, 3, 5, 5, 3
Males (Population 2): 5, 5, 6, 4, 4, 6, 3, 3, 3, 5
Give a 92.3% confidence interval for the difference between mean female and male drink consumption. (Assume that the population variances are equal.)
Confidence Interval =
Solutions
Expert Solution
| P1 | P2 | |
| 2 | 5 | |
| 2 | 5 | |
| 2 | 6 | |
| 1 | 4 | |
| 3 | 4 | |
| 1 | 6 | |
| 3 | 3 | |
| 5 | 3 | |
| 5 | 3 | |
| 3 | 5 | |
| Mean | 2.7 | 4.4 |
| SD | 1.418136492 | 1.173787791 |
Excel formulas:
mean = Average(B2:B11)
SD = STDEV(B2:B11)
orchestra answered 2 years agoRelated Solutions
Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic...
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