Question

In: Math

In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed...

In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 2446 subjects randomly selected from an online group involved with ears. 1083 surveys were returned. Construct a 99​% confidence interval for the proportion of returned survey.

Solutions

Expert Solution

Solution :

Given that,

n = 2446

x = 1083

Point estimate = sample proportion = = x / n = 0.443

1 - = 0.557

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 2.576 * (((0.443 * 0.557) / 2446)

= 0.026

A 99% confidence interval for population proportion p is ,

- E < p < + E

0.443 - 0.026 < p < 0.443 + 0.026

0.417 < p < 0.469

The 99% confidence interval is : (0.417 , 0.469)

milcah answered 1 year ago
Next > < Previous

Related Solutions

In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 2616 subjects randomly selected from an online group involved with ears.1023 surveys were returned. Construct a 99​% confidence interval for the proportion of returned surveys. 1. find the best point estimate of the population proportion p ( round to three decimal places as needed) 2. identify the value of the margin of error E 3. Construct the convidence interval ____<p<______ 4. write a...
In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone use and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 2592 subjects randomly selected from an online group involved with ears. 913 surveys were returned. Construct a 99​% confidence interval for the proportion of returned surveys.
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6985 subjects randomly selected from an online group involved with ears. There were 1295 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1299 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6978 subjects randomly selected from an online group involved with ears. There were 1331 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6978 subjects randomly selected from an online group involved with ears. There were 1331 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed...
In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6980 subjects randomly selected from an online group involved with ears. There were 1332 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. A. Upper H 0​: pequals0.2 Upper H...
In a study of cellphone use and brain hemispheric dominance, an Internet survey was e-mailed to...
In a study of cellphone use and brain hemispheric dominance, an Internet survey was e-mailed to 5000 subjects randomly selected from an online group involved with ears. 717 surveys were returned. Use a 0.01 significance level to test the claim that the return rate is less than 15%.
In the study of cell phone use and brain hemispheric dominance, an internet survey was emailed...
In the study of cell phone use and brain hemispheric dominance, an internet survey was emailed to 2524 subjects randomly selected from an online group involved with ears. 930 surveys were returned. Construct a 99% confidence interval for the proportion of returned surveys. A. Find the best point estimate of the population proportion p B. Identify the value of the margin of error E. C. Construct the confidence interval
In a study of cell phone use and brain hemispheric dominance, an internet survey was emailed...
In a study of cell phone use and brain hemispheric dominance, an internet survey was emailed to 2601 subjects randomly selected from an online group involved with ears. 975 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys. a) What is the best point estimate of the population P c) Construct the confidence level b) Identify the value of the margin of error E. c) Construct the confidence level.
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT