In: Statistics and Probability
In a study of cellphone use and brain hemispheric dominance, an Internet survey was e-mailed to 5000 subjects randomly selected from an online group involved with ears. 717 surveys were returned. Use a 0.01 significance level to test the claim that the return rate is less than 15%.
Here we have to test
n = Total number of subjects selected randomly from an online group = 5000
x = Number of subjects were returned = 717
Here
and
So conditions are satisfied.
Test statistic:
Where
= 0.00505 (Round to 5 decimal)
Z = -1.31 (Round to 2 decimal)
P value = P(Z < -1.31)
= 0.0951 (From statistical table of z values)
Level of significance = alpha = 0.01
Here P value = 0.0951 > alpha = 0.01
So we do not reject H0.
Conclusion: There is insufficient evidence to conclude that the return rate is less than 15%