Question

Write the complete ionic and net ionic equations for all of the reactions listed

(a) KOH_(aq) + HCl_(aq) H₂O_(l) + KCl _(aq)

(b) 2 Na_(s) + Cl_2(g) 2 NaCl _(s)

(c) Ca(NO₃)_2(aq) + Na₂CO_3(aq) 2 NaNO_3(aq) + CaCO_3(s)   

(d) HBr _(aq) + Cl_2(g) 2HCl _(aq) + Br_2(l)   

(e) 2 C₂H_6(g) + 7 O_2(g) 4 CO_2(g) + 6 H₂O _(g)

Answer 1

Complete ionic equation : This represent all the ions involved in reaction.

Net ionic equation: This represent only those ions which take parti in reaction it does not include spectator ions. spectator ions are those ions which remain in solution.

(a)Complete ionic equation :  

K⁺ (aq) + OH^-(aq) + H⁺ (aq)+ Cl^- (aq) ===> K⁺(aq) + Cl^-(aq)+ H2O(l)

Here  K⁺ (aq), Cl^- (aq) will be spectator ions.

Net ionic equation : OH^-(aq) + H⁺(aq) ===>  H₂O(l)

(b) No dissociation of ions will occur so complete ion equation and net ionic equation will be same as : 2 Na(s) + Cl₂(g) ===> 2 NaCl (s)

(c) Complete ionic equation :

2Ca ²⁺(aq)+  2NO₃^-(aq) + 2Na⁺(aq) + 2CO₃^2-(aq) ===>  2NO₃^-(aq) + 2Na⁺(aq) + CaCO₃(s)

NO₃^-(aq) and Na⁺(aq) will be spectator ions .

Net ionic equation:  

2Ca ²⁺(aq)+ 2CO₃^2-(aq)  ===> 2CaCO₃(s)

(d) Complete ionic equation :

2H⁺(aq) + 2Br^-(aq) + Cl₂(g)===> 2H⁺ (aq) + 2Cl^- (aq) + Br₂(l)

H⁺(aq)  is spectator ion.

Net ionic equation

2Br^-(aq) + Cl₂(g) ===> 2Cl^- (aq) + Br₂(l)

(e) Complete ionic equation and net ionic equation will be same as no dissociation of ions will occur.

2C₂H₆(g) + 7O₂(g) ===> 4CO₂(g) + 6H₂O (g)