Question

Puzzle #4

Five friends each wrote a letter to Santa Claus, pleading for certain presents. What is the full

name of each letter-writer and how many presents did he or she ask for? Kids’ names: Danny,

Joelle, Leslie, Sylvia, and Yvonne. Last names: Croft, Dean, Mason, Palmer, and Willis. Number

of presents requested: 5, 6, 8, 9, and 10.

Clues:

1. Danny asked for one fewer present that the number on Yvonne’s list.

2. The child surnamed Dean asked for one more present than the number on the list written by

the child surnamed Palmer.

3. Sylvia’s list featured the fewest presents, and the letter written by the child surnamed Willis

featured the highest quantity.

4. Joelle asked for one fewer present than the number specified in the Croft child’s letter.

Make your grid to solve:

Answer 1

3. Sylvia’s list featured the fewest presents, and the letter written by the child surnamed Willis

featured the highest quantity.

Sylvia = 5, Willis = 10

1. Danny asked for one fewer present that the number on Yvonne’s list.

Danny = 8 , Yvonne = 9 or

Danny = 9 , Yvonne = 10

2. The child surnamed Dean asked for one more present than the number on the list written by

the child surnamed Palmer.

Dean = 6, Palmer = 5 or

Dean = 9, Palmer = 8

4. Joelle asked for one fewer present than the number specified in the Croft child’s letter.

Joelle = 5, Croft = 6 or

Joelle = 8, Croft = 9

So, Danny=8 or 9, Joelle = 5 or 8, Sylvia = 5, Yvonne = 9 or 10

  Croft = 6 or 9, Dean = 6 or 9, Palmer = 5 or 8, and Willis = 10

Here only 6 remains that will go to Leslie Leslie = 6

10 can only go to Yvonne Yvonne = 10 Danny = 9 , Yvonne = 10

Now Danny can't take 8, 8 will go to Joelle Joelle = 8   Joelle = 8, Croft = 9

Now Croft can't take 6, 6 will go to Dean Dean = 6 Dean = 6, Palmer = 5

Now only 8 remain that will go to Mason Mason = 8

Danny Croft = 9

Joelle Mason = 8

Leslie Dean = 6

Sylvia Palmer = 5

Yvonne Willis = 10