Question

In: Chemistry

A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility...

A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic acid in 100mL of water is 0.54 g at 14C and 18 g at 99C. The smallest volume of boiling water the student could use to dissolve 500 mg of phthalic acid is 2.778 mL of water.

Dissolution of phthalic acid in boiling water produced a dark-colored solution. The student allowed the solution to cool, added several spatulas full of activated carbon, and heated the mixture to boiling. After gravity filtration, the clear and colorless solution was allowed to cool to room temperature. Crystals formed, and the student isolated 380 mg of phthalic acid.

a) Calculate the percent recovery of phthalic acid in this experiment.
b) Suggest one or more procedural errors the student made that could be responsible for some loss of phthalic acid.

Solutions

Expert Solution

Given:
the published solubilities of phthalic aicd are
0.54g/100mL at 14C
18g / 100mL at 99C

a) Since the solubility of the acid is more when water is at 99C therefore
smallest volume of boiling water = 500mg / (18g/100mL)
= 0.5g / (18g /100mL)
= 2.78mL

Percent recovery of the acid = {(380mg) / (500mg)}x100
= 76%

b) possible causes is that recrystallization...and during filteration.


Related Solutions

The solubility of phthalic acid in water is 0.54 g/100 mL at 14 C and 18...
The solubility of phthalic acid in water is 0.54 g/100 mL at 14 C and 18 g/100 mL at 99 C.What is the smallest volume of boiling water that should be used to recrystallize 600 mg of phthalic acid from hot water? You will have to recrystallize many compounds throughout organic I and II. Write a short procedure on how you would do a simple recrystallization( no hot gravity filtration involved). Assume you know which solvent to use but not...
Can an impure sample of oleic acid be purified by recrystallization? Justify your answer for full...
Can an impure sample of oleic acid be purified by recrystallization? Justify your answer for full credit.
The “impure” phthalic acid was mixed with a known (to the instructor but not the student)...
The “impure” phthalic acid was mixed with a known (to the instructor but not the student) amount of resorcinol. Can you determine the amount of resorcinol (percentage) contained in the impure phthalic acid sample? Explain why or why not. Why factors play an important role in making this determination.
A student weighted out 100mg sample semi-pure sample of salicylic acid. After recrystallization from ethyl acetate,...
A student weighted out 100mg sample semi-pure sample of salicylic acid. After recrystallization from ethyl acetate, the yield was was 22mg. (A) Where is the remaining compound, (B) why is it there, and (C) how can the yield be improved? (the answer is not simply concentrate the filtrate and recrystallize from ethyl acetate again) Answer A, B, and C in complete sentences.
Can an impure sample of citronellal be purified by recrystallization? Justify your answer.
Can an impure sample of citronellal be purified by recrystallization? Justify your answer.
How can phthalic acid not be soluble in water in both hot or cold temperatures?
How can phthalic acid not be soluble in water in both hot or cold temperatures?
A 425 mg sample of a weak diprotic acid is dissolved in enough water to make...
A 425 mg sample of a weak diprotic acid is dissolved in enough water to make 275.0 ml of solution. The pH of this solution is 3.08. A saturated solution of calcium hydroxide (Ksp= 1.3 x 10-6) is prepared by adding excess calcium hydroxide to water and then removing the undissolved solid by filtration. Enough of the calcium hydroxide solution is added to the solution of the acid to reach the second equivalence point. The pH at the second equivalence...
A 425 mg sample of a weak diprotic acid is dissolved in enough water to make...
A 425 mg sample of a weak diprotic acid is dissolved in enough water to make 275.0 ml of solution. The pH of this solution is 3.08. A saturated solution of calcium hydroxide (Ksp= 1.3 x 10^-6) is prepared by adding excess calcium hydroxide to water and then removing the undissolved solid by filtration. Enough of the calcium hydroxide solution is added to the solution of the acid to reach the second equivalence point. The pH at the second equivalence...
The solubility of O2 (g) in water at 0 oC = 14.74 mg/L. The solubility decreases...
The solubility of O2 (g) in water at 0 oC = 14.74 mg/L. The solubility decreases to 7.03 mg/L at 35 oC. Calculate kH (Henry’s Law Constant) for water at these temperatures. partial pressure=0.21
The solubility of Mg(OH)2 in water is approximately 9 mg/L. (a) Calculate the Ksp of magnesium...
The solubility of Mg(OH)2 in water is approximately 9 mg/L. (a) Calculate the Ksp of magnesium hydroxide. (b) Calculate the hydroxide concentration needed to precipitate Mg2+ ions such that no more than 5.0 μg/L Mg2+ remains in solution. (c) Calculate the maximum concentration of Mg2+ (as M) that can exist in a solution of pH = 12.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT