In: Chemistry
In 1925, E. Gorter and F. Grendel, studied erythrocytes from a dog and obtained data similar to the following: volume of packed cells (38 mL); number of cells (7.96 x 106 per mm3); Total surface area of lipid monolayer from cells (63 m2); Total surface area of one cell (98 μm2). Calculate the total surface area (in terms of μm2 to the nearest ones) of lipid monolayer per cell. Think about whether the figure you calculated supports the claim that cell membranes are composed of a bilayer.
Ans. Given,
Total packed volume of cells = 38 mL
Cell density = 7.96 x 106 cells/ mm3 ; [1 mm3 = 0.001 mL]
= 7.96 x 109 cells/ mL
Total surface area of lipid monolayer = 63 m2 ; [1 m = 106 um]
= 63 x (106 um)2
= 6.3 x 1013 um2
Now,
Total number of cells in 38 mL sample = Cell density x packed volume
= (7.96 x 109 cells/ mL) x 38 mL
= 3.0248 x 1011 cells
Now,
Surface area of lipid monolayer per cell = Total area of lipid monolayer / Number of cells
= (6.3 x 1013 um2) / (3.0248 x 1011 cells)
= 208.28 um2 / cell
= 208 um2 / cell
# Each cell is made up of lipid bilayer. A bilayer consists of two sheets of the monolayer.
So,
Total surface area of lipid bilayer per cell = (Surface area of lipid monolayer per cell) / 2
= (208 um2 / cell) / 2
= 104 um2 / cell
Therefore, total surface area of a cell (enclosed by lipid bilayer) = 104 um2 / cell
# Comparison: The calculated value of lipid bilayer surface area per cell of 104 um2/ cell is in close agreement with the given value of 98 um2/ cell.