In Fig. 8.3, a bullet of mass 0.01 kg moving horizontally strikes a block of wood...

In Fig. 8.3, a bullet of mass 0.01 kg moving horizontally strikes a block of wood of mass 1.5 kg which is suspended as a pendulum. The bullet lodges in the wood, and together they swing upward a distance of 0.40 m. What was the velocity of the bullet just before it struck the wooden block? The length of the string is 2 meters.

Solutions

Expert Solution

Gravitational acceleration = g = 9.81 m/s²

Mass of the bullet = m = 0.01 kg

Mass of the block = M = 1.5 kg

Initial speed of the bullet = V₁

Speed of the block and bullet immediately after the collision = V₂

By conservation of linear momentum,

Height to which the block and bullet rise after the collision = h = 0.4 m

Length of the string attached to the block = L = 2 m

By conservation of energy the kinetic energy of the block and bullet immediately after the collision is converted into the potential energy of the block and bullet as they go up.

V₁ = 423 m/s

Velocity of the bullet just before it struck the wooden block = 423 m/s

genius_generous answered 8 months ago

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