In: Statistics and Probability
The following table shows a company's annual revenue (in billions of dollars) for 2009 to 2014.
Year | Period (t) | Revenue ($ billions) |
---|---|---|
2009 | 1 | 23.6 |
2010 | 2 | 29.2 |
2011 | 3 | 37.8 |
2012 | 4 | 50.3 |
2013 | 5 | 59.8 |
2014 | 6 | 66.6 |
a)
What type of pattern exists in the data?
The time series plot shows an upward curvilinear trend.
The time series plot shows a downward curvilinear trend.
The time series plot shows a downward linear trend.
The time series plot shows an upward linear trend.
(b)
Develop a linear trend equation for this time series to forecast revenue (in billions of dollars). (Round your numerical values to three decimal places.)
Tt = ____
(c)
What is the average revenue increase per year (in billions of dollars) that this company has been realizing? (Round your answer to three decimal places.)
$ ____ billion
(d)
Compute an estimate of this company's revenue (in billions of dollars) for 2015. (Round your answer to two decimal places.)
$ ____ billion
X | Y | XY | X² | Y² |
1 | 23.6 | 23.6 | 1 | 556.96 |
2 | 29.2 | 58.4 | 4 | 852.64 |
3 | 37.8 | 113.4 | 9 | 1428.84 |
4 | 50.3 | 201.2 | 16 | 2530.09 |
5 | 59.8 | 299 | 25 | 3576.04 |
6 | 66.6 | 399.6 | 36 | 4435.56 |
Ʃx = | Ʃy = | Ʃxy = | Ʃx² = | Ʃy² = |
21 | 267.3 | 1095.2 | 91 | 13380.13 |
Sample size, n = | 6 |
x̅ = Ʃx/n = 21/6 = | 3.5 |
y̅ = Ʃy/n = 267.3/6 = | 44.55 |
SSxx = Ʃx² - (Ʃx)²/n = 91 - (21)²/6 = | 17.5 |
SSyy = Ʃy² - (Ʃy)²/n = 13380.13 - (267.3)²/6 = | 1471.915 |
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 1095.2 - (21)(267.3)/6 = | 159.65 |
a)
The time series plot shows an upward linear trend.
b)
Slope, b = SSxy/SSxx = 159.65/17.5 = 9.122857143
y-intercept, a = y̅ -b* x̅ = 44.55 - (9.12286)*3.5 = 12.62
Regression equation :
ŷ = 12.62 + (9.123) x
c)
average revenue increase per year = 9.123 billion
d)
Predicted value of y at x = 7
ŷ = 12.62 + (9.1229) * 7 = 76.48 billion