In: Chemistry
In order to find the rate constant for a third order rate law, you should
(a)Take the slope of 1/ [A] vs time
(b)Take the slope of 1/ [A] vs temp
(c)Take the slope of Ln [A] vs time
(d)Take the slope of Ln [A] vs temp
(e)Use the rate law
The best way to identify fast and easy the rate of reaction AND the rate constant is via Graphical Method.
First, as the name implies, we need to graph all types of order (most common)
Zero = C vs t;
For zero order, there is no dependency of concentrations:
dC/dt = k*C^0
dC/dt = k
When developed:
C = C0 - kt
if x axis is "time" then the slope is "k", and y-intercept is initial concentration C0. y-axis if C (concentration)
First = ln(C) vs. t
For first order
dC/dt = k*C^1
dC/dt = k*C
When developed:
dC/C = k*dt
ln(C) = ln(C0) - kt
if x axis is "time" then the slope is "-k", and y-intercept is initial concentration C0. y-axis if ln(C) (natural logarithm of concentration)
Second = 1/C vs. t
For Second order
dC/dt = k*C^2
When developed:
dC/C^2 = k*dt
1/C= 1/C0 + kt
if x axis is "time" then the slope is "k", and y-intercept is initial concentration C0. y-axis if 1/(C (inverse of concentration)
Third = 1/C2 vs. t
For Thirdorder
dC/dt = k*C^3
When developed:
dC/C^3 = k*dt
1/C^2= 1/C0^2 + kt
then, we need to
there is no option shown
therefore, the best thing to do is
(e)Use the rate law
that is, get 1 point, substitute
Rate = k*[A]^3
rate, and concentration of A
k = Rate/[A]^3
solve for k, then you rill get k