In: Physics
The spin cycles of a washing machine have two angular speeds, 416 rev/min and 632 rev/min . The internal diameter of the drum is 0.560 m
Part A
What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed? (F higher/F lower)=?
Part B
What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed? (V higher/ V lower)=?
Part C
Find the laundry's maximum tangential speed . (m/s)
Part D
Find the laundry's maximum radial acceleration, in terms of g . (a rad=? g)
Given that
The spin cycles of a washing machine have two angular speeds(w1) =416 rev/min =416*2pi/60 =43.541rad/s
angular speed(w2) = 632 rev/min =632*2pi/60 =66.149rad/s
The internal diameter of the drum is(D) = 0.560 m and the radius is (R) =0.280m
a)What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed is given by
Force (F) =ma =mw2r
The maximum radial force is =mw2R
Therefore
Fhigher/Flower =(whigher/wlower)2 =(66.149/43.541)2 =(1.5912)2 =2.308
b)
What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed is given by
Tangential speed(v) =wr
Max tangential speed is v =wR
So, vhigher/vlower =(whigher/wlower) =66.149/43.541 =1.5912
c)
Find the laundry's maximum tangential speed is given by v =whigher*R =(66.149)(0.280) =18.521m/s
d)
Find the laundry's maximum radial acceleration, in terms of g is given by
a =whigher2R =(66.149)2*(0.280) =1225.193m/s2=124.89g