In: Statistics and Probability
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36. Is there evidence at the 0.050.05 level that the technique lengthens the training time?
Step 2 of 6 :
Find the value of the test statistic. Round your answer to two decimal places.
Solution:
Given in the question
The claim is that the technique lengthens the training time.
Null hypothesis H0:
= 92 hours
Alternate hypothesis Ha:
> 92 hours
Sample mean(Xbar) = 93
Population variance = 36
So Population standard deviation ()
= 6
No. of sample n = 70
So test statistic value can be calculated as
Test statistic = (Xbar -
)//sqrt(n)
= (93 - 92)/6/sqrt(70) = 1.39
Here we will Z test sample size is greater than 30 and the
population standard deviation is also known. So p-value from Z
table can be found as this is a right-tailed test so P-value =
0.0816
Here at alpha = 0.05, we can are failed to reject the null
hypothesis as the p-value is greater than alpha value so we dont
have significant evidence to support the claim that the technique
lengthens the training time.