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Assuming capture and recovery efficiencies of 98% and 97% respectively, show that 1,000 ton/day of CO2...

Assuming capture and recovery efficiencies of 98% and 97% respectively, show that 1,000 ton/day of CO2 would correspond to capturing most of the carbon emissions from a 50 MWe plant fired with coal. State all your assumptions including fuel H/C ratio, and fuel-to-electricity conversion efficiency. How would your answer change if the electrical output of the plant remained the same but you switched from coal to natural gas as the fuel?

Solutions

Expert Solution

CO2 captured and recovered per day = 1000*0.98*0.97 = 950.6 ton/day

CO2 captured and recovered in kg per day = 950.6*907.185 = 8.62 x 105 kg/day

Now, because for coal H/C ratio is found to be near 0.8 from literature.

So, 1 mol of coal approximately weighs = 12 g C + 0.8 g H = 12.8g/mol

Also, 1 g of CO2 weighs to be 44 g/mol.

So, coal that must neen used to generate this much CO2 is = (8.62 x 105 ) * (12.8/44) kg/day

= 2.5 * 105 kg/day

Now, for sake of simplicity, let us assume the calorific value for coal is around 3000kcal/kg and fuel to electricity conversion efficiency is 60%.

So, enegy generated per day= 2.5 * 105 * 3000 * 4.184 = 3.14 * 109 kJ/day

energy needed by plant per day = 50 * 103 *24 * 3600 = 4.32 * 109 kJ/day.

Thus, the energy needed is more than that can be generated from CO2 . Thus, all the CO2 produced can be utilized to generate the energy for the plant.

Now, if we change to natural gas, natural gas has a high H/C ratio of about to be 4.0 and calorific value is very high equal to 12500 kcal/kg(as compared to coal). So, there will be a high amount of excess CO2 will be produced.


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