Question

• Make a function that calculates the summation of even numbers in the range.

• The function sum takes the two integer parameters and they are used as the range.

  • The function uses default parameters for the range. When we call this function with one argument, it will be used as a starting point and the end of the range will be 100. Also, the function is called without any argument, the default range (0,100) will be used.

We will use default parameters 0 and 100 for each parameter respectively.

• For example,
  sum(20, 50) : sum of even numbers between 20 and 50.
  sum(30) : The second parameter is a default value. The range will be (30, 100)
  sum( ) : Both parameters are default values. The range will be (0, 100)

Answer 1

As it is not defined in which language it is to be coded, So seeing the constraints I coded it in C++ which is easily understandable abd comments are being added wherever necesary.

CODE:

#include <iostream>
using namespace std;

class evenNumber
{
  
public:
  
// Member Function handles all the cases as defined in problem
void sum(int x=0, int y=100)
{
   //add keeps track of addition of even numbers between the range
   int l,add=0;
       //initialising l with first even number in the range
if(x%2==0){
    l=x+2;
}
else{
    l=x+1;
}
//performing the summation
for(int i=l;i<y;i=i+2){
    add=add+i;
}
cout<<"summation of range is :"<<add<<endl;
}
};
int main() {
   // your code goes here
   //object created of class evenNumber to perform or call the functions
   evenNumber ob;
   //functions are called with different parameters
   ob.sum(2,81);
   ob.sum(5);
   ob.sum();
   return 0;
}

OUTPUT:

Success #stdin #stdout 0s 4276KB

summation of range is :1638
summation of range is :2444
summation of range is :2450