Question

A long jumper leaves the ground with initial vertical velocity of 4.0 m.s-1 and an initial horizontal velocity of 3.0 m.s-1.

How do you find the total flight time and horizontal distance traveled?

Answer 1

We have given that

And

Total flight time will be given by

Acceleration due to gravity we have taken as

So we get

T=8/10=0.8 second

And

Horizontal distance is given by

Since during the projectile motion

So

So v= 5 m/s

Now

So we have now

Since

So

So

R=2.4 m

If we take the acceleration due to gravity as

Then

Time of flight

T=8/9.8

T= 0.8163265306122 second

And

Horizontal distance will be

R=24/9.8

R=2.4489795918367 meter