In: Chemistry
A reaction vessel at 1215 K contains a mixture of
SO2(P= 3.10 bar ) and O2(P= 1.20 bar ). When a
catalyst is added the reaction
2SO2(g)+O2(g)⇌2SO3(g)
takes place. At equilibrium the total pressure is 4.05 bar .
2SO2(g)+O2(g)⇌2SO3(g)
I 3.1 1.2 0
C -2x -x +2x
E 3.1-2x 1.2-x +2x
total pressure at equilibrium = 4.05bar
PSO2 + PO2 + PSo3 = 4.05
3.1-2x +1.2-x + 2x = 4.05
x = 0.25
PSO2 = 3.1-2x = 3.1-2*0.25 = 2.6bar
PO2 = 1.2-x = 1.2-0.25 = 0.95bar
PSO3 = 2x = 2*0.25 =0.5 bar