Question

In: Chemistry

he reversible chemical reaction A(aq)+B(aq)⇌C(aq)+D(aq) has the following equilibrium constant: K=[C][D][A][B]=2.4 What is the final concentration...

he reversible chemical reaction

A(aq)+B(aq)⇌C(aq)+D(aq)

has the following equilibrium constant:

K=[C][D][A][B]=2.4

What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 mol⋅L−1 and [B] = 2.00 mol⋅L−1 ?

Solutions

Expert Solution

                 A(aq)+B(aq)⇌C(aq)+D(aq)

            I     1          2           0        0

           C    -x        -x            +x       +x

           E    1-x      2-x            +x       +x

    K=[C][D]/[A][B]=2.4

       [C][D]/[A][B]=2.4

      x*x/(1-x)*(2-x) = 2

       x^2                = 2*(1-x)*(2-x)

         x = 0.764

     [D] = x= 0.764M

         


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