he reversible chemical reaction A(aq)+B(aq)⇌C(aq)+D(aq) has the following equilibrium constant: K=[C][D][A][B]=2.4 What is the final concentration...

he reversible chemical reaction

A(aq)+B(aq)⇌C(aq)+D(aq)

has the following equilibrium constant:

K=[C][D][A][B]=2.4

What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 mol⋅L−1 and [B] = 2.00 mol⋅L−1 ?

Expert Solution

A(aq)+B(aq)⇌C(aq)+D(aq)

I 1 2 0 0

C -x -x +x +x

E 1-x 2-x +x +x

K=[C][D]/[A][B]=2.4

[C][D]/[A][B]=2.4

x*x/(1-x)*(2-x) = 2

x^2 = 2*(1-x)*(2-x)

x = 0.764

[D] = x= 0.764M

queen_honey_blossom answered 2 years ago

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