1) The correct arrangement of the following complex ions in terms of increasing crystal field splitting...

1) The correct arrangement of the following complex ions in terms of increasing crystal field splitting energy (D) is:

[CrI₆]^3- [CrF₄]^- [Cr(en)₃]³⁺ [W(en)₃]³⁺

a) Smallest [CrI₆]^3- < [Cr(en)₃]³⁺ < [CrF₄]^- < [W(en)₃]³⁺ Largest

b) Smallest [CrI₆]^3- < [W(en)₃]³⁺ < [CrF₄]^- < [Cr(en)₃]³⁺ Largest

c) Smallest [CrF₄]^- < [CrI₆]^3- < [Cr(en)₃]³⁺ < [W(en)₃]³⁺ Largest

d) Smallest [CrF₄]^- < [W(en)₃]³⁺ < [CrI₆]^3- < [Cr(en)₃]³⁺ Largest

e) Smallest [W(en)₃]³⁺ < [Cr(en)₃]³⁺ < [CrF₄]^- < [CrI₆]^3- Largest

2) Determine the number of unpaired electrons for each of the following coordination complexes:

[Ni(H₂O)₆]²⁺

[CoCl₆]^2–

Cr(CO)₆

[Pt(CN)₄]^2–

Arrange these complexes in order of increasing number of unpaired electrons (in the answers below an = sign is used if two complexes have the same number of electrons).

a) Fewest [Pt(CN)₄]^2– < [Ni(H₂O)₆]²⁺ < Cr(CO)₆ < [CoCl₆]^2– Greatest

b) Fewest [Pt(CN)₄]^2– = Cr(CO)₆ < [CoCl₆]^2– < [Ni(H₂O)₆]²⁺ Greatest

c) Fewest [Pt(CN)₄]^2– < Cr(CO)₆ < [CoCl₆]^2– < [Ni(H₂O)₆]²⁺ Greatest

d) Fewest [Pt(CN)₄]^2– < Cr(CO)₆ < [Ni(H₂O)₆]²⁺ < [CoCl₆]^2– Greatest

e) Fewest [Pt(CN)₄]^2– = Cr(CO)₆ < [Ni(H₂O)₆]²⁺ < [CoCl₆]^2– Greatest

Solutions

Expert Solution

queen_honey_blossom answered 8 months ago

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