Question

1. dd a new function that is similar to the counting function that you already have - but which uses a for loop to do the exact same thing (count from n//2 to n). Your solution must use a for loop with a range function.
2. Instrument your code by adding print functions so that we can tell which function is doing the counting, as shown in the sample output below.
3. Modify your program so that it alternates between using your for loop function and your while loop function each time a number is entered, as shown in the sample output.
4. Make sure your output exactly matches what is shown below.

Sample session:

C:> python whileloop3.py

Enter a number: 2

Counting with 'while' ... 1 2

total = 2

Enter a number: 2

Counting with 'for' ... 1 2

total = 4

Enter a number: 3

Counting with 'while' ... 1 2 3

total = 7

Enter a number: 3

Counting with 'for' ... 1 2 3

total = 10

Enter a number: 1

Counting with 'while' ... 0 1

total = 11

Enter a number: 1

Counting with 'for' ... 0 1

total = 12

Enter a number: 3

total = 15, exiting

the code:

def look():
    p = int(input("Put a number: "))
    i = p//2-1

    while i < p:
        i = i+1
        print(i ,end=" ")



if __name__ == "__main__":
    look()

Answer 1

Here is code:

def look():

    sum = 0

    choice = 'y'

    while choice == 'y':

        p = int(input("Put a number: "))

        i = p//2

        sum += p

        for it in range(i, p+1):

            print(it, end=" ")

        print("\nTotal = ", sum)

        choice = input("Do you want to continue (n/y) : ")

if __name__ == "__main__":

    look()

Output: