Determine if the following series converge or diverge. If it
converges, find the sum.
a. ∑n=(3^n+1)/(2n) (upper limit of sigma∞, lower limit is
n=0)
b.∑n=(cosnπ)/(2) (upper limit of sigma∞ , lower limit is n=
1
c.∑n=(40n)/(2n−1)^2(2n+1)^2 (upper limit of sigma ∞ lower limit
is n= 1
d.)∑n = 2/(10)^n (upper limit of sigma ∞ , lower limit of sigma
n= 10)
1. Given the series:
∞∑k=1 2/k(k+2)
does this series converge or diverge?
converges
diverges
If the series converges, find the sum of the series:
∞∑k=1 2/k(k+2)=
2. Given the series:
1+1/4+1/16+1/64+⋯
does this series converge or diverge?
diverges
converges
If the series converges, find the sum of the series:
1+1/4+1/16+1/64+⋯=
If the sequence is increasing then it a) converges to its
supremum b) diverges c) may converge to its supremum d) is
bounded
if S= { 1/n - 1/m: n,m belongs to N } where N is the set of
natural numbers then infimum and supremum of S respectively are a)
-1and 1 b) 0,1 c)0,0 d)can not be determined
Please explain
Please solve fully
Determine whether the geometric series is convergent or
divergent. If it is convergent, find its sum.8 − 11 +
121
8
−
1331
64
+
Step 1
To see 8 − 11 +
121
8
−
1331
64
+ as a geometric series, we
must express it as
∞
ar n − 1
n = 1
.
For any two successive terms in the geometric series
∞
ar n − 1
n = 1
, the ratio of...