In: Statistics and Probability
Problem 1:
A research laboratory was developing a new compound for the relief of severe cases of hay fever. In an experiment with 36 volunteers, the amounts of the two active ingredients (A & B) in the compound were varied at three levels each. Randomization was used in assigning four volunteers to each of the nine treatments. The data on hours of relief can be found in the following .csv file: Fever.csv
1.1) State the Null and Alternate Hypothesis for conducting one-way ANOVA for both the variables ‘A’ and ‘B’ individually.
1.6) Mention the business implications of performing ANOVA for this particular case study.
A | B | Volunteer | Relief |
1 | 1 | 1 | 2.4 |
1 | 1 | 2 | 2.7 |
1 | 1 | 3 | 2.3 |
1 | 1 | 4 | 2.5 |
1 | 2 | 1 | 4.6 |
1 | 2 | 2 | 4.2 |
1 | 2 | 3 | 4.9 |
1 | 2 | 4 | 4.7 |
1 | 3 | 1 | 4.8 |
1 | 3 | 2 | 4.5 |
1 | 3 | 3 | 4.4 |
1 | 3 | 4 | 4.6 |
2 | 1 | 1 | 5.8 |
2 | 1 | 2 | 5.2 |
2 | 1 | 3 | 5.5 |
2 | 1 | 4 | 5.3 |
2 | 2 | 1 | 8.9 |
2 | 2 | 2 | 9.1 |
2 | 2 | 3 | 8.7 |
2 | 2 | 4 | 9 |
2 | 3 | 1 | 9.1 |
2 | 3 | 2 | 9.3 |
2 | 3 | 3 | 8.7 |
2 | 3 | 4 | 9.4 |
3 | 1 | 1 | 6.1 |
3 | 1 | 2 | 5.7 |
3 | 1 | 3 | 5.9 |
3 | 1 | 4 | 6.2 |
3 | 2 | 1 | 9.9 |
3 | 2 | 2 | 10.5 |
3 | 2 | 3 | 10.6 |
3 | 2 | 4 | 10.1 |
3 | 3 | 1 | 13.5 |
3 | 3 | 2 | 13 |
3 | 3 | 3 | 13.3 |
3 | 3 | 4 | 13.2 |
Null Hypothesis: the two active ingredients (A & B) are same
Alternative Hypothesis: the two active ingredients (A & B) are not same
we conduct factorial experiment
and we perform in minitab software
Factorial Fit: Relief versus A, B, Volunteer
* NOTE * This design has some botched runs. It will be analyzed
using a
regression
approach.
Estimated Effects and Coefficients for Relief (coded units)
Term
Effect Coef SE
Coef T
P
Constant
7.18333 0.1477 48.63 0.000
A
5.95000 2.97500 0.1809 16.44 0.000
B
4.35000 2.17500 0.1809 12.02 0.000
Volunteer -0.00667
-0.00333 0.1982 -0.02 0.987
A*B
2.58750 1.29375 0.2216 5.84
0.000
A*Volunteer 0.02000
0.01000 0.2427 0.04 0.967
B*Volunteer -0.01000 -0.00500 0.2427
-0.02 0.984
A*B*Volunteer -0.03750 -0.01875 0.2973 -0.06 0.950
S = 0.886292 PRESS = 34.4507
R-Sq = 94.13% R-Sq(pred) = 90.81% R-Sq(adj)
= 92.66%
Analysis of Variance for Relief (coded units)
Source
DF Seq SS Adj SS Adj
MS
F P
Main Effects 3
325.950 325.950 108.650 138.32 0.000
A
1 212.415 212.415 212.415 270.42 0.000
B
1 113.535 113.535 113.535 144.54 0.000
Volunteer
1 0.000 0.000
0.000 0.00 0.987
2-Way Interactions 3 26.782
26.782 8.927 11.37 0.000
A*B
1 26.781 26.781
26.781 34.09 0.000
A*Volunteer
1 0.001 0.001
0.001 0.00 0.967
B*Volunteer
1 0.000 0.000
0.000 0.00 0.984
3-Way Interactions 1
0.003 0.003
0.003 0.00 0.950
A*B*Volunteer 1
0.003 0.003
0.003 0.00 0.950
Residual Error 28
21.994 21.994 0.786
Total
35 374.730
Unusual Observations for Relief
Obs StdOrder Relief Fit SE Fit Residual
St Resid
17 17 8.9000 7.1867
0.2472 1.7133
2.01R
18 18 9.1000 7.1844
0.1618 1.9156
2.20R
20 20 9.0000 7.1800
0.2472 1.8200
2.14R
R denotes an observation with a large standardized residual.
Estimated Coefficients for Relief using data in uncoded units
Term
Coef
Constant
2.20556
A
0.30833
B
-0.46667
Volunteer -0.058889
A*B
1.32500
A*Volunteer 0.031667
B*Volunteer 0.021667
A*B*Volunteer -0.012500
* NOTE * Some factors have more than 2 levels, no alias table
was printed.
Residual Plots for Relief