In: Math
Consider the following hypothesis test.
H0: μ ≤ 12
Ha: μ > 12
A sample of 25 provided a sample mean
x = 14
and a sample standard deviation
s = 4.37.
(a)
Compute the value of the test statistic. (Round your answer to three decimal places.)
(b)
Use the t distribution table to compute a range for the p-value.
p-value > 0.200
0.100 < p-value < 0.200
0.050 < p-value < 0.100
0.025 < p-value < 0.050
0.010 < p-value < 0.025
p-value < 0.010
(c)
At
α = 0.05,
what is your conclusion?
Reject H0. There is sufficient evidence to conclude that μ > 12.
Do not reject H0. There is sufficient evidence to conclude that μ > 12.
Do not reject H0. There is insufficient evidence to conclude that μ > 12.
Reject H0. There is insufficient evidence to conclude that μ > 12.
(d)
What is the rejection rule using the critical value? (If the test is one-tailed, enter NONE for the unused tail. Round your answer to three decimal places.)
test statistic≤
test statistic≥
What is your conclusion?
Reject H0. There is sufficient evidence to conclude that μ > 12.
Do not reject H0. There is sufficient evidence to conclude that μ > 12.
Do not reject H0. There is insufficient evidence to conclude that μ > 12.
Reject H0. There is insufficient evidence to conclude that μ > 12.
Solution :
Given that,
Population mean = = 12
Sample mean = = 14
Sample standard deviation = s = 4.37
Sample size = n = 25
Level of significance = = 0.05
This is a right - tailed test.
a)
The test statistics,
t = ( - )/ (s/)
= ( 14 - 12 ) / ( 4.37 /35)
= 2.708
b)
P- Value = 0.0053
p-value < 0.010
c)
= 0.05
The p-value is p =0.0053 < 0.05, it is concluded that the null hypothesis is rejected.
Reject H0. There is sufficient evidence to conclude that μ > 12.
d)
Critical value of the significance level is α = 0.05, and the critical value for a right-tailed test is
= 1.691
Since it is observed that t = 2.708 = 1.691, it is then concluded that the null hypothesis is rejected.
Reject H0. There is sufficient evidence to conclude that μ > 12.