In: Statistics and Probability
A study of 40 physicians showed that they spent an average of 16.2 minutes per patient. Find the 95% confidence interval of the true mean for the average time spent with patients when the standard deviation = 3 minutes.
Solution :
Given that,
Point estimate = sample mean = =16.2
Population standard deviation =
= 3
Sample size n =40
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.96 * (3 / 40 )
= 0.9297
At 95% confidence interval estimate of the population mean
is,
- E <
<
+ E
16.2 -0.9297 <
<16.2 +0.9297
15.2703 <
< 17.1297
( 15.2703 ,17.1297 )