Question

int[]array={90, 57, 34, 81, 59, 51, 99, 52, 78, 67}; use for numbers 1 through 4

1. Write code to create two int arrays called odd and even of length 10. Populate the arrays with even numbers in the even array and odd numbers in the odd array as you go through the int[]array [ reminder 7%2 is 1, 8%2 is 0. The modulus operator yields the remainder]. Do not worry about the 0’s that are not filled.

2. Write code to go through the array and increase any number < 50 by 20.

3. Write code to find the average of the given array.

Write code to print the given array backwards

Answer 1

public class Main
{
   public static void main(String[] args) {
      
       int[]array={90, 57, 34, 81, 59, 51, 99, 52, 78, 67};
       System.out.println("originalarray is : ");
       print(array);
       evenOdd(array);
       increase(array);
       average(array);
       backward(array);
   }
   static void print(int[] list)
   {
   for(int i=0;i<list.length;i++)
   {
   System.out.print(list[i]+" ");
   }
   }
  
   static void evenOdd(int[] list)
   {
   int[] even=new int[10];
   int[] odd=new int[10];
   int i1=0;
   int j=0;
  
   for(int i=0;i<list.length;i++)
   {
   if(list[i]%2==0)
   {
   even[i1++]=list[i];
     
   }
   if(list[i]%2==1)
   {
   odd[j++]=list[i];
     
   }
   }
   System.out.println("\nodd array is : ");
   print(odd);
   System.out.println("\neven array is : ");
   print(even);
  
   }
  
       static void increase(int[] list)
   {
   for(int i=0;i<list.length;i++)
   {
   if(list[i]<50)
   {
   list[i]+=20;
   }
   }
   System.out.println("\narray increase by 20 : ");
   print(list);
   }
      static void average(int[] list)
   {
   float sum=0;
   for(int i=0;i<list.length;i++)
   {
   sum=sum+list[i];
   }
   System.out.println("\naverage is : "+sum/list.length);
   }
   static void backward(int[] list)
   {
   System.out.println("backward array is : ");
   for(int i=list.length-1;i>=0;i--)
   {
   System.out.print(list[i]+" ");
   }
   }
  
}