Question

In: Biology

This problem has two parts: Part 1. In one of Mendel’s dihybrid crosses, he observed 315...

This problem has two parts:

Part 1.

In one of Mendel’s dihybrid crosses, he observed 315 round, yellow, 108 round, green, 101 wrinkled, yellow, and 32 wrinkled, green F2s. Analyze these data using the χ2test to see if they fit: (a) a 9:3:3:1 ratio and (b) the round: wrinkled data fit a 3:1 ratio. Show all of your work.

Part 2.

For both (a) and (b) of the problem above, what does the calculated p-value mean (i.e. what is the probability the difference between your expected and observed data  is due to chance)?

Solutions

Expert Solution

Answer:

Part1:

a).

Then, let us try whether they fit in 9:3:3:1 ration…

Dihybrid F2 phenotypic ratio = 9:3:3:1

Total progeny = 315+108+101+32 = 556

Round, yellow = 9/16* 556

Round, green = 3/16*556

Wrinkled, yellow = 3/16*556

Wrinkled, green = 1/16*556

Phenotype

Observed(O)

Expected (E)

O-E

(O-E)2

(O-E)2/E

round, yellow

315

312.750

2.25

5.06

0.0162

round, green

108

104.250

3.75

14.06

0.1349

wrinkled, yellow

101

104.250

-3.25

10.56

0.1013

wrinkled, green

32

34.750

-2.75

7.56

0.2176

Total

556

556

0.4700

X^2 value = 0.47

Degrees of freedom = Number of phenotypes – 1

Df = 4-1=3

P value = 7.815

The chi-square value of 0.47 is less than the critical value of 7.815. We can accept the null hypothesis and the data is fit in 9:3:3:1.

b). The data doesn’t fit in to the 3:1 ratio as 4 types of traits are found.

Part 2:

a).

Degrees of freedom = Number of phenotypes – 1

Df = 4-1=3

P value = 7.815 (stadard value)

b). Degrees of freedom = Number of phenotypes – 1

Df = 2-1=1

P value = 3.84 (stadard value)


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