In: Biology
This problem has two parts:
Part 1.
In one of Mendel’s dihybrid crosses, he observed 315 round, yellow, 108 round, green, 101 wrinkled, yellow, and 32 wrinkled, green F2s. Analyze these data using the χ2test to see if they fit: (a) a 9:3:3:1 ratio and (b) the round: wrinkled data fit a 3:1 ratio. Show all of your work.
Part 2.
For both (a) and (b) of the problem above, what does the calculated p-value mean (i.e. what is the probability the difference between your expected and observed data is due to chance)?
Answer:
Part1:
a).
Then, let us try whether they fit in 9:3:3:1 ration…
Dihybrid F2 phenotypic ratio = 9:3:3:1
Total progeny = 315+108+101+32 = 556
Round, yellow = 9/16* 556
Round, green = 3/16*556
Wrinkled, yellow = 3/16*556
Wrinkled, green = 1/16*556
Phenotype |
Observed(O) |
Expected (E) |
O-E |
(O-E)2 |
(O-E)2/E |
round, yellow |
315 |
312.750 |
2.25 |
5.06 |
0.0162 |
round, green |
108 |
104.250 |
3.75 |
14.06 |
0.1349 |
wrinkled, yellow |
101 |
104.250 |
-3.25 |
10.56 |
0.1013 |
wrinkled, green |
32 |
34.750 |
-2.75 |
7.56 |
0.2176 |
Total |
556 |
556 |
0.4700 |
X^2 value = 0.47
Degrees of freedom = Number of phenotypes – 1
Df = 4-1=3
P value = 7.815
The chi-square value of 0.47 is less than the critical value of 7.815. We can accept the null hypothesis and the data is fit in 9:3:3:1.
b). The data doesn’t fit in to the 3:1 ratio as 4 types of traits are found.
Part 2:
a).
Degrees of freedom = Number of phenotypes – 1
Df = 4-1=3
P value = 7.815 (stadard value)
b). Degrees of freedom = Number of phenotypes – 1
Df = 2-1=1
P value = 3.84 (stadard value)