Question
In: Chemistry
CH3NH2 is a weak base (Kb = 5.0 × 10–4) and so the salt, CH3NH3NO3, acts...
CH3NH2 is a weak base (Kb = 5.0 × 10–4) and so the salt, CH3NH3NO3, acts as a weak acid. What is the pH of a solution that is 0.0490 M in CH3NH3NO3 at 25 °C?
Solutions
Expert Solution
CH3NH3+ +
H2O 
H3O+
+ CH3NH2
Initial 0.049 M 0 0
Change -x +x +x
Equilibrium (0.049-x) x x
Ka = Kw/Kb = (10-14)/(5 x 10-4) = x2/(0.049-x)
2 x 10-11 = x2/(0.049)
x = 9.89 x 10-7 M
pH = -log(9.89 x 10-7 M) = 6.00
pH = 6
queen_honey_blossom answered 2 years agoRelated Solutions
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