Question

In: Chemistry

Consider the following reaction. 5 H2C2O4 + 2 MnO4− + 6 H + → 10 CO2...

Consider the following reaction. 5 H2C2O4 + 2 MnO4− + 6 H + → 10 CO2 + 2 Mn2+ + 8 H2O Oxalic acid How many milliliters of 0.1210 M KMnO4 are needed to react with 137.0 mL of 0.1210 M oxalic acid? ___ mL How many milliliters of 0.1210 M oxalic acid are required to react with 137.0 mL of 0.1210 M KMnO4? ___ mL

Expert Solution

KMnO4 H2C2O4

M1= 0.1210M M2= 0.1210M

V1= V1 = 137.0mL

n1= 2 n2= 5

M1V1/n1 = M2V2/n2

V1 = M2V2/n2 xn1/M1

V1 = 0.1210 x137x2/5x0.1210

V1 = 54.8mL

Volume of KMnO4 needed= 54.8mL

b) KMnO4 h2C2O4

M1 = 0.1210M M2 = 0.1210M

V1 = 137mL V2 =

n1 = 2 mole n2 = 5 mole

V2 = M1V1n2/n1M2

= 0.1210x137x5/2x0.1210

= 342.5mL

Volume of Oxalic acid needed = 342.5ml

queen_honey_blossom answered 2 years ago

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