In: Math
Consider the function q(x)=x^11−3x^10+2. Find the x-coordinates of all local maxima. If there are multiple values, give them separated by commas. If there are no local maxima, enter ∅.
Let x = c is the critical point of f(x) it means f'(x) = 0 at x = c than according to first derivative test we can write,
1) if f'(x) changes from positive to negative at x = c than x = c is local maximum
2) if f'(x) changes from negative to positive at x = c than x = c is local minimum
we have,
we can write,
equate it to 0 we can write,
Hence we can say that x = 0 and x = 30/11 are critical points of the function q(x)
Divide the interval (-infinity, infinity) into three intervals given by (-infinity, 0), (0, 30/11) and (30/11, infinity)
now check the sign of q'(x) on these interval
To check the sign of q'(x) on interval (-infinity, 0) evaluate q'(x) at x = -1 and x = -2
we can write,
Hence we can say that q'(x) > 0 means positive on the interval (-infinity, 0)
To check the sign of q'(x) on interval (0, 30/11) evaluate q'(x) at x = 1 and x = 2
we can write,
Hence we can say that q'(x) < 0 means negative on the interval (0, 30/11)
To check the sign of q'(x) on interval (30/11, infinity) evaluate q'(x) at x = 3 and x = 4
we can write,
Hence we can say that q'(x) > 0 means positive on the interval (30/11, infinity)
we know that local extremum is the value of x where f'(x) changes its sign
we know that to find the x coordinates of local maxima it means according to first derivative test we have to find the value of x at which f'(x) changes from positive to negative
we can write,
q'(x) > 0 means positive on the interval (-infinity, 0)
q'(x) < 0 means negative on the interval (0, 30/11)
q'(x) > 0 means positive on the interval (30/11, infinity)
we can see that at x = 0 f'(x) changes from positive to negative hence we can say that x = 0 is the local maximum
we can write local maximum is given by x = 0
Note : here we have check random values of x to find the sign of f'(x) on respective interval we can take any x value in those intervals.